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M 5 Assignment

M 5 Assignment

Q Please answer the question below. There is an extra credit SPSS question available below the required question. Burglary data are presented below, based on neighborhood and victim race variables. Conduct a clearly stated five-step hypothesis test, using chi-square and an alpha level of .05, to assess whether there is a bivariate relationship between neighborhood and victim race. Additional tables are provided to assist you and should be completed. Worth 10 points. Number of Burglaries Occurring Yearly: Neighborhood Victim Race Citrus Grove Heights White 34 35 20 Black 12 36 18 Hispanic 8 3 0 Neighborhood Victim Race Citrus Grove Heights Row Marginal White 34 35 20 Black 12 36 18 Hispanic 8 3 0 Column Marginal Step 1: State the H0 and the H1. Step 2: Identify the distribution and compute the df. Step 3: Identify the critical value of the test statistic, and state the decision rule. Step 4: Compute the obtained value of the test statistic. Round all numbers to 2 decimals. Cell fo fe (fo–fe) (fo–fe)2 (fo–fe)2/fe White (Citrus) White (Grove) White (Heights) Black (Citrus) Black (Grove) Black(Heights) Hispanic (Citrus) Hispanic (Grove) Hispanic (Heights) Step 5: Conclusion * Extra credit SPSS Analysis: Using the data set posted in Canvas (in the Syllabus section), compute and interpret the following. You can attach or copy and paste your SPSS output tables to support your answer. Worth a total of 5 extra credit points. Run a chi-square test with “transfer” as the independent variable on the rows, and “convict” as the dependent variable on the columns. In running the test, mark and interpret the chi-square statistic, phi and Cramer’s V, and the row percentages. Interpret the results.

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1. Null hypothesis: H0: There is no relationship between the Victim Race and neighbourhood Alternative Hypothesis: H1: There is a relationship between the Victim Race and neighbourhood 2. It will follow a chi-square distribution Degree of Freedom (DF): (r-1)(c-1) = (3-1) (3-1)= 2*2 = 4